Liberian Palm Oil Stew
Liberian palm oil stew is a delicious and hearty dish from Liberia. Made with a rich combination of palm oil, vegetables, and protein, this stew is a staple in Liberian cuisine and is often served with rice or fufu.
Ingredients
- 1 cup palm oil
- 1 onion, finely chopped
- 2 cloves of garlic, minced
- 1 green bell pepper, diced
- 1 red bell pepper, diced
- 1 Scotch bonnet chile pepper, finely chopped (optional, for spiciness)
- 1 pound chicken, cut into pieces
- 2 cups chicken broth
- 1 pound fish, cut into steaks or fillets
- ½ pound okra, sliced
- 1 eggplant, diced
- Salt, to taste
- Ground black pepper, to taste
Instructions
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1In a large pot, heat the palm oil over medium heat.
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2Add the chopped onion and minced garlic to the pot. Sauté until the onion becomes translucent and fragrant.
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3Stir in the diced green and red bell peppers and chopped Scotch bonnet pepper (if using). Cook for a few minutes until the peppers start to soften.
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4Add the chicken pieces to the pot and cook until they are lightly browned on all sides.
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5Pour in the chicken broth and bring the mixture to a simmer. Cover the pot and let the chicken cook for about 20–25 minutes, or until it is fully cooked and tender.
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6Once the chicken is cooked, add the fish steaks or fillets to the pot and let them simmer in the stew for an additional 5–10 minutes, or until they are cooked through.
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7Stir in the sliced okra and diced eggplant. Let the stew simmer for another 5–7 minutes, or until the vegetables are tender.
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8Season the stew with salt and ground black pepper to taste. Adjust the seasoning according to your preference.
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9Remove the pot from the heat and let the stew rest for a few minutes before serving.
- Category
- Soups
Recipe Attribution
Wikibooks Cookbook
Printed from recipe.exchange
https://recipe.exchange/recipes/wb-457472
Printed on October 30, 2026